0=5x^2-4x+6

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Solution for 0=5x^2-4x+6 equation: 



0=5x^2-4x+6

We move all terms to the left:

0-(5x^2-4x+6)=0

We add all the numbers together, and all the variables

-(5x^2-4x+6)=0

We get rid of parentheses

-5x^2+4x-6=0

a = -5; b = 4; c = -6;
Δ = b2-4ac
Δ = 42-4·(-5)·(-6)
Δ = -104
Delta is less than zero, so there is no solution for the equation

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